[1/4x-3=1/2x+12

Solution for [1/4x-3=1/2x+12 equation:

1/4x-3=1/2x+12

We move all terms to the left:

1/4x-3-(1/2x+12)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x+12)!=0

x∈R


We get rid of parentheses

1/4x-1/2x-12-3=0

We calculate fractions


2x/8x^2+(-4x)/8x^2-12-3=0

We add all the numbers together, and all the variables

2x/8x^2+(-4x)/8x^2-15=0

We multiply all the terms by the denominator


2x+(-4x)-15*8x^2=0

Wy multiply elements

-120x^2+2x+(-4x)=0

We get rid of parentheses

-120x^2+2x-4x=0

We add all the numbers together, and all the variables

-120x^2-2x=0

a = -120; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-120)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-120}=\frac{0}{-240}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-120}=\frac{4}{-240}
=-1/60
$